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denim2323

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An object has the most kinetic energy at **b. Bottom**, just before it hits the ground.

At which point during a drop does an object have the most kinetic energy? a.After it hits the ground b.Bottom c.Top d.Middle

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Illustration of various organisms, including plants and animals, surrounded by colorful energy representations like sunlight, electrical sparks, and chemical structures to signify the types of energy they use.

The type of energy that organisms use to live a.Thermal b.Electrical c.Mechanical d.Chemical

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$To calculate the kinetic energy of the girl right before she hits the water, we can use the principle of conservation of energy. The potential energy (PE) at the height of the diving board will convert to kinetic energy (KE) just before she hits the water. The formula for potential energy is: \[ PE = mgh \] where: - $ m = 50 $ kg (mass of the girl), - $ g = 9.81 $ m/s² (acceleration due to gravity), - $ h = 5 $ m (height of the diving board). Now, calculating the potential energy: \[ P$ A 50Kg girl jumps off a 5-meter-high diving board. What is her kinetic energy right before she hits the water? a.2450 J b.25 J c.0 J d.1225 J

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To determine which ball bounces with the most efficiency, we can calculate the efficiency of each bounce using the formula for bounce efficiency, which is the ratio of the height the ball bounces back to the height from which it was dropped.

1. **Ball dropped from 10m, bounces to 2m:**
Efficiency = 2m / 10m = 0.2 (20%)

2. **Ball dropped from 12m, bounces to 10m:**
Efficiency = 10m / 12m = 0.833 (83.3%)

3. **Ball dropped from 10m, bounces to 6m:**
Efficiency = 6m / 10m = 0.6 (60

Which ball bounces with the most efficiency? A ball dropped from 10m that bounces to a new height of 2m A ball dropped from 12m that bounces to a new height of 10m A ball dropped from 10m that bounces to a new height of 6m A ball dropped from 12m that bounces to a new height of 6m

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Illustration of a tightly coiled spring, showcasing its ability to store mechanical energy.

What is a device that can store mechanical energy? Spring Battery Generator Food

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Illustration comparing four objects: a baseball and a bowling ball held waist high, and a baseball and a bowling ball held shoulder high, emphasizing their positions to demonstrate gravitational potential energy.

Which object probably has the most gravitational potential energy? A baseball held waist high A bowling ball held waist high A baseball held shoulder high A bowling ball held shoulder high

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An infographic showing the concept of mechanical energy, illustrating the sum of potential energy and kinetic energy with corresponding visuals for each type of energy.

The sum of a systems Potential Energy and Kinetic Energy is equal to what? Mechanical Energy Chemical Energy Thermal Energy Electrical Energy

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$To determine the mechanical energy transferred from the ball to the environment, we can calculate the gravitational potential energy (PE) at the initial height and the potential energy at the height to which it bounces back. 1. **Initial height (h1)**: 3 m 2. **Final height (h2)**: 1.2 m 3. **Mass (m)**: 0.08 kg 4. **Acceleration due to gravity (g)**: 9.8 m/s² (approximately) **Step 1: Calculate the initial potential energy (PE_initial) at height 3 m.** \[ \text{PE_initial} = m \cdot g \$ A .08Kg ball is dropped from a height of 3m. The ball bounces back up to a height of 1.2m. How much mechanical energy was transferred from the ball to the environment? 1.8 J .94 J 1.41 J 2.35 J

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$To determine how high the cannonball will travel, we can use the formula for the maximum height $ h $ reached by an object launched vertically, which is given by: \[ h = \frac{v^2}{2g} \] where: - $ v $ is the initial velocity (25 m/s), - $ g $ is the acceleration due to gravity (approximately 9.81 m/s²). Plugging in the values: \[ h = \frac{(25 \, \text{m/s})^2}{2 \times 9.81 \, \text{m/s}^2} = \frac{625}{19.62} \approx 31.89 \, \text{m} \] Therefore, the correct answer is **31.89 m*$ A cannon shoots a 200Kg cannonball straight up into the air. The cannonball leaves the cannon at 25m/s. How high will the cannonball travel? 125,012.67 m 6,377.55 m 31.89 m 62,500 m

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$To calculate the kinetic energy of the man when he is 20 meters from the water, we start by determining his potential energy at the initial height and then how much potential energy has converted to kinetic energy as he falls. 1. **Initial height**: 50 meters 2. **Height when 20 meters from the water**: 50 - 20 = 30 meters 3. **Potential Energy (PE) at 30 meters**: \[ PE = mgh = 100 \text{ kg} \times 9.81 \text{ m/s}^2 \times 30 \text{ m} = 29,430 \text{ J} \] 4. **Potential Energy ($ A 100 Kg man is diving off a 50-meter cliff. What is his kinetic energy when he is 20 meters from the water? 29,400 J 10,000 J 19,600 J 49,000J

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When the kid is halfway down the jump, they will have converted some of their potential energy into kinetic energy. At the top of the jump, the potential energy is 1,000 J.

As they descend to halfway, their potential energy will decrease. Since they are halfway down, they will have half of their initial potential energy remaining:

- Potential energy at halfway down = 1,000 J / 2 = 500 J

The total energy (potential + kinetic) remains constant (assuming no energy loss), so:

- Total mechanical

A kid on a trampoline has 1,000 J of potential energy when they are at the top of a jump. How much kinetic energy will the kid have when they come halfway down? 250 J 1000 J 500 J 100 J

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Illustration showing a falling object at different points: top, middle, bottom, and after hitting the ground, with arrows indicating kinetic energy increasing as it falls.

At which point during a drop does an object have the most kinetic energy? After it hits the ground Bottom Top Middle

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$To determine the velocity of the watermelon right before it hits the ground, we can use the formula for the final velocity of an object in free fall: \[ v = \sqrt{2gh} \] where: - $ v $ is the final velocity, - $ g $ is the acceleration due to gravity (approximately $ 9.81 \, \text{m/s}^2 $), - $ h $ is the height from which the object is dropped (8 meters in this case). Plugging in the values: \[ v = \sqrt{2 \times 9.81 \, \text{m/s}^2 \times 8 \, \text{m}} \] \[ v = \sqrt{157.28}$ A 2.5 Kg watermelon is dropped off an 8-meter balcony. What will the watermelon’s velocity be right before it hits the ground? 196 m/s 12.52 m/s 8.23 m/s 156.8 m/s

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$To find the mechanical energy of the ball, we can use the formula for mechanical energy, which is the sum of kinetic energy (KE) and potential energy (PE). 1. **Calculate Kinetic Energy (KE)**: \[ KE = \frac{1}{2} mv^2 \] Where: - $ m = 0.1 \, \text{kg} $ - $ v = 12 \, \text{m/s} $ \[ KE = \frac{1}{2} \times 0.1 \times (12)^2 = \frac{1}{2} \times 0.1 \times 144 = 7.2 \, \text{J} \] 2. **Calculate Potential Energy (PE)**: \[ PE = mgh \] Where: - \($ A .1Kg ball is dropped off a ledge. The ball is travelling 12m/s when it is 3m from the ground. How much mechanical energy is in the ball? 2.94 J 0 J 7.2 J 10.14 J

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