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Question: what is the point of the line y-8=\frac{1}{3}\left(x+10\right)
The equation you've provided, \(y - 8 = \frac{1}{3}(x + 10)\), is in point-slope form. The point-slope form of a line is generally represented as: \[ y - y_1 = m(x - x_1) \] where \((x_1, y_1)\) is a point on the line and \(m\) is the slope of the line. In your equation: - \(m\) (the slope) is \(\frac{1}{3}\). - The point on the line \((x_1, y_1)\) can be derived by comparing with the general form. Here, \(y_1 = 8\) and \(x + 10\) suggests \(x_1 = -10\). So, the point on the line is \((-10, 8)\). Therefore, the equation represents a line with a slope of \(\frac{1}{3}\) that passes through the point \((-10, 8)\).
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