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Question: What is the kinetic energy of a 1-kilogram ball is thrown into the air with an initial velocity of 30 m/sec? list the given required and solution
To find the kinetic energy of a 1-kilogram ball thrown into the air with an initial velocity of 30 m/s, we can use the following formula: \[ \text{Kinetic Energy (KE)} = \frac{1}{2} m v^2 \] Where: - \( m \) is the mass of the object - \( v \) is the velocity of the object **Given:** - Mass (\( m \)) = 1 kilogram - Initial velocity (\( v \)) = 30 meters per second **Required:** - Kinetic energy (\( \text{KE} \)) **Solution:** Substitute the known values into the kinetic energy formula: \[ \text{KE} = \frac{1}{2} \times 1 \, \text{kg} \times (30 \, \text{m/s})^2 \] First, calculate the square of the velocity: \[ (30 \, \text{m/s})^2 = 900 \, (\text{m/s})^2 \] Now multiply by the mass: \[ \frac{1}{2} \times 1 \, \text{kg} \times 900 \, (\text{m/s})^2 = \frac{1}{2} \times 900 \, \text{kg} \,\text{m}^2/\text{s}^2 \] Finally, calculate the result: \[ \text{KE} = \frac{1}{2} \times 900 \, \text{J} \] \[ \text{KE} = 450 \, \text{J} \] So, the kinetic energy of the ball is 450 joules.
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