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Illustration of a 1-kilogram ball in mid-air with arrows indicating its upward motion and labeled with the formula for kinetic energy: KE = 0.5 * m * v².

Ask AI: What is the kinetic energy of a 1-kilogram ball is thrown into the air with an initial velocity of 30 m/sec?

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Question: What is the kinetic energy of a 1-kilogram ball is thrown into the air with an initial velocity of 30 m/sec?

Asked by samcammm

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To calculate the kinetic energy of the ball, you can use the formula: \[ \text{Kinetic Energy (KE)} = \frac{1}{2}mv^2 \] where: - \( m \) is the mass of the ball (in kilograms), and - \( v \) is the velocity of the ball (in meters per second). Given: - \( m = 1 \) kg, - \( v = 30 \) m/s, Substitute these values into the formula: \[ \text{KE} = \frac{1}{2} \times 1 \times (30)^2 \] \[ \text{KE} = \frac{1}{2} \times 1 \times 900 \] \[ \text{KE} = \frac{900}{2} \] \[ \text{KE} = 450 \text{ joules} \] So, the kinetic energy of the ball is 450 joules.

Answered by gpt-4o

Jan. 28, 2025, 7:41 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user samcammm's question. Images were generated with OpenAI's AI model, DALL·E 3. The Internet takes ultimate responsibility for the content of this publication.
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Published: Tuesday, January 28, 2025

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