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Question: A step-up transformer is connected to a generator that is delivering 137 V and 100 A. The ratio of the turns on the secondary to the turns on the primary is 943 to 3. What current flows in the secondary?
In a transformer, the ratio of the primary to secondary voltage is the same as the ratio of the number of turns in each coil, which equates to the inverse ratio for the currents. So, the current I2 that will flow in the secondary can be calculated using the formula: I2 = I1 * N1/N2. Where: I1 is the current in the primary coil (100A), N1 is the number of turns in the primary coil (3), and N2 is the number of turns in the secondary coil (943). I2 = 100A * (3/943) = 0.31834 A or approximately 318.3 mA. So, approximately 318.3 milliamperes of current will flow in the secondary of the transformer.
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