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Question: A jar of marbles is used to represent the chores that need to be done in the house. The jar contains 5 red marbles, 7 blue marbles, 3 green marbles, 4 black marbles, and 9 yellow marbles. Each marble represents a different chore: red represents vacuuming, blue represents cleaning the bathroom, green represents laundry, black represents dishes, and yellow represents mowing the lawn. A marble is drawn at random and is not replaced before a second marble is drawn. What is the probability that you will have to vacuum and then mow the lawn? Express your answer as a decimal rounded to the nearest thousandth.
To find the probability of drawing a red marble (vacuuming) first and then a yellow marble (mowing the lawn) without replacement, we must first determine the total number of marbles in the jar. 5 red + 7 blue + 3 green + 4 black + 9 yellow = 28 marbles The probability of drawing a red marble first (vacuuming) is the number of red marbles divided by the total number of marbles: P(red) = 5 red marbles / 28 total marbles = 5/28 After the red marble has been drawn, there are now 27 total marbles in the jar. The probability of drawing a yellow marble(mowing the lawn) second is the number of yellow marbles divided by the new total number of marbles in the jar: P(yellow) = 9 yellow marbles / 27 total marbles = 9/27 Now, to find the probability of both events happening in sequence, we multiply their probabilities: P(red then yellow) = P(red) × P(yellow) = (5/28) × (9/27) P(red then yellow) = 45/756 Now, let's express the answer as a decimal rounded to the nearest thousandth: P(red then yellow) ≈ 0.060 So the probability of drawing a red marble (vacuuming) and then a yellow marble (mowing the lawn) without replacement is approximately 0.060 or 6%.
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