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Question: You and your friend go to a carnival. One of the games is a bean bag toss. In this game, you have 3 tries to try to land a bean bag in the hole to win a prize. If you have an 87% chance of missing the target, what is the probability of you winning? Write your answer as a percentage, rounded to the nearest tenth.
To find the probability of you winning the game, we first need to find the probability of you missing all 3 attempts. Since you have an 87% chance of missing the target for each attempt, the probability of missing all 3 attempts is 0.87 * 0.87 * 0.87 = 0.658503. Now, to find the probability of winning, we subtract the probability of missing all 3 attempts from 1: 1 - 0.658503 = 0.341497 Converting this probability to a percentage and rounding to the nearest tenth, we get: 0.341497 * 100 = 34.1% So, you have a 34.1% chance of winning the bean bag toss game.
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