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Question: A jar of marbles is used to represent the chores that need to be done in the house. The jar contains 5 red marbles, 7 blue marbles, 3 green marbles, 4 black marbles, and 9 yellow marbles. Each marble represents a different chore: red represents vacuuming, blue represents cleaning the bathroom, green represents laundry, black represents dishes, and yellow represents mowing the lawn. A marble is drawn at random and is not replaced before a second marble is drawn. What is the probability that you will have to vacuum and then mow the lawn? Express your answer as a decimal rounded to the nearest thousandth.
To find the probability of selecting a red marble (vacuuming) first and then a yellow marble (mowing the lawn), you need to use the formula for probability when drawing without replacement: (number of desired outcomes) / (total number of possible outcomes). For the first draw, there are 5 red marbles out of a total of 28 marbles (5 red + 7 blue + 3 green + 4 black + 9 yellow = 28). So the probability of drawing a red marble first is 5/28. For the second draw, there is now one less marble in the jar, so there are a total of 27 marbles. Since you want to draw a yellow marble next, there are 9 yellow marbles left. So, the probability of drawing a yellow marble after drawing a red marble is 9/27. To find the probability of both events occurring in sequence, you need to multiply the probabilities together: (5/28) * (9/27) You can simplify the fractions by dividing the numerator and denominator with common factors: (5/28) * (1/3) = (5*1)/(28*3) = 5/84 Now, convert this fraction to a decimal by dividing the numerator by the denominator: 5 ÷ 84 ≈ 0.0595 When you round to the nearest thousandth, you get: 0.060 Therefore, the probability of having to vacuum and then mow the lawn when drawing two marbles without replacement is approximately 0.060.
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