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Question: A(n) 0.157 kg baseball is thrown with a speed of 28.2 m/s. It is hit straight back at the pitcher with a final speed of 15.2 m/s. What is the magnitude of the impulse delivered to the ball?
Impulse is calculated as the change in momentum. Momentum is mass times velocity, so the change in momentum would be final momentum minus initial momentum. The initial momentum (Pi) can be found by multiplying the mass of the baseball by the speed at which it was thrown: Pi = m * vi = 0.157 kg * 28.2 m/s = 4.4274 kg*m/s And the final momentum (Pf) is the mass of the baseball times the speed it was hit back: Pf = m * vf = 0.157 kg * 15.2 m/s = 2.3854 kg*m/s The impulse (J) which is the change in momentum can be calculated as: J = Pf - (- Pi) = 2.3854 kg*m/s - (- 4.4274 kg*m/s) = 2.3854 kg*m/s + 4.4274 kg*m/s = 6.8128 kg*m/s Therefore, the magnitude of the impulse delivered to the ball is 6.8128 kg*m/s.
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