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Question: The load across a 12 V battery consists of a series combination of three resistors 24.1 Ω, 45.9 Ω, and 58.8 Ω. what is the current in the circuit?
The total resistance in a series circuit is the sum of the individual resistances. So you would add the three resistances together to get the total resistance. R(total) = R1 + R2 + R3 R(total) = 24.1 Ω + 45.9 Ω + 58.8 Ω R(total) = 128.8 Ω Ohm's Law can be used to calculate the current in the circuit. Ohm's Law states that the current (I) is equal to the voltage (V) divided by the resistance (R). I = V / R I = 12V / 128.8Ω I = 0.093 Amps So, the current in the circuit is approximately 0.093 Amps.
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