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Question: The first term is 1 and the second term 2. The rest of the terms are found by adding the two terms before it together, and then doubling the answer.
It sounds like you're trying to describe a sequence where each term (starting from the third term) is found by adding the two previous terms and then doubling the result. Let's define this sequence step by step. 1. The first term (\(a_1\)) is 1. 2. The second term (\(a_2\)) is 2. 3. For \(n \geq 3\), the \(n\)-th term (\(a_n\)) is found by the formula: \[ a_n = 2 \times (a_{n-1} + a_{n-2}) \] Let's compute a few terms of this sequence to understand the pattern: 1. \( a_1 = 1 \) 2. \( a_2 = 2 \) 3. \( a_3 = 2 \times (a_2 + a_1) = 2 \times (2 + 1) = 2 \times 3 = 6 \) 4. \( a_4 = 2 \times (a_3 + a_2) = 2 \times (6 + 2) = 2 \times 8 = 16 \) 5. \( a_5 = 2 \times (a_4 + a_3) = 2 \times (16 + 6) = 2 \times 22 = 44 \) 6. \( a_6 = 2 \times (a_5 + a_4) = 2 \times (44 + 16) = 2 \times 60 = 120 \) So the first six terms of the sequence are: 1, 2, 6, 16, 44, 120. If you need more terms or further assistance with this sequence, feel free to ask!
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