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Question: The expression (x) (x−17)is equivalent to xn. What is the value of n ?
To determine the value of \( n \) in the expression \( (x)(x - 17) = x^n \), we need to simplify the left-hand side of the equation. Start by expanding the expression: \[ (x)(x - 17) = x \cdot x - x \cdot 17 \] \[ = x^2 - 17x \] Now, we compare this with the form \( x^n \). The expression \( x^2 - 17x \) contains both \( x^2 \) and a term with \( x \), which means it is not a single term that can be expressed solely in the form \( x^n \). Therefore, the expression \( (x)(x - 17) \) cannot be represented as \( x^n \) for any single value of \( n \) because it is a polynomial of degree 2 with a linear term, rather than a single power of \( x \).
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