Ask AI on The Internet
Question: An automobile vehicle weighing 13.5 kN is moving on a level road at a speed of 95 km/h. When the brakes are applied, it is subjected to a uniform deceleration of 6 m/s2. There are brakes on all four wheels. The tyre diameter is 750 mm. The kinetic energy of the rotating parts is 10% of the kinetic energy of the moving vehicle. The mass of each brake drum assembly is 10 kg and the specific heat capacity is 460 J/kg°C. Calculate (i) the braking time; (ii) the braking distance; (iii) the total energy absorbed by each brake; (iv) the torque capacity of each brake; and (v) the temperature rise of brake drum assembly.
(i) To calculate the braking time, we can use the formula: t = (final velocity - initial velocity) / deceleration First, we need to convert the initial velocity (95 km/h) to meters per second (m/s): Initial velocity = 95 km/h * (1000 m/km) * (1 h/3600 s) = 26.39 m/s Since the vehicle comes to a stop, the final velocity = 0 m/s. Then, we can find braking time: t = (0 - 26.39 m/s) / (-6 m/s²) = 4.4 s (ii) To calculate the braking distance, we can use the formula: Braking distance = initial velocity * time + 0.5 * deceleration * time² Braking distance = 26.39 m/s * 4.4 s + 0.5 * (-6 m/s²) * (4.4 s)² = 57.85 m (iii) To find the total energy absorbed by each brake, we need to find the kinetic energy (KE) of the vehicle first: KE = 0.5 * mass * initial_velocity² Given that an automobile vehicle weighs 13.5 kN, we first convert it to mass (kg): Mass = 13.5 kN * (1000 N/kN) / 9.81 m/s² = 1375.38 kg Now, we find the kinetic energy of the vehicle: KE = 0.5 * 1375.38 kg * (26.39 m/s)² = 476528.05 J As mentioned in the problem, the kinetic energy of the rotating parts is 10% of the kinetic energy of the moving vehicle: Rotating parts KE = 476528.05 J * 10% = 47652.80 J Then, subtract the rotating parts' kinetic energy from the total kinetic energy to get the energy absorbed by the brakes: Energy absorbed by brakes = 476528.05 J - 47652.80 J = 428875.25 J Since there are 4 brakes, the total energy absorbed by each brake is: Energy absorbed by each brake = 428875.25 J / 4 = 107218.81 J (iv) To find the torque capacity of each brake, we can first find the angular deceleration (α) using the formula: α = deceleration / radius Given the tire diameter of 750 mm, the radius is 375 mm or 0.375 m. Now, we can find the angular deceleration: α = 6 m/s² / 0.375 m = 16 rad/s² Now, we can find the torque capacity using the formula: Torque capacity = moment of inertia (I) * α The moment of inertia (I) of each brake drum assembly can be found using the formula: I = 0.5 * m * r², where m is the mass and r is the radius With a mass of 10 kg for each brake drum assembly, the moment of inertia is: I = 0.5 * 10 kg * (0.375 m)² = 0.703 kg·m² Now, we can find the torque capacity: Torque capacity = 0.703 kg·m² * 16 rad/s² = 11.25 N·m (v) To find the temperature rise of the brake drum assembly, we can use the formula: Temperature rise = (Energy absorbed by each brake) / (mass of brake drum assembly * specific heat capacity) Temperature rise = 107218.81 J / (10 kg * 460 J/kg°C) = 23.3°C
A new large language model has been made available since this question was asked.
To generate an updated answer from the new model, click the button below.
Think your answer is better than the AI's? Post it below.
Other Most Relevant Posts:
Question Tags
If you want your question answered by an AI, click here.
Post your own comment: