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The braking time is 2.7 s. The braking distance is 4.2 m. The total energy absorbed by each brake is 65 J. The torque capacity of each brake is 400 Nm. The temperature rise of brake drum assembly is 11°C.

The braking time is 8.4 s. The braking distance is 960 mm. The total energy absorbed by each brake is 27 kJ. The torque capacity of each brake is 8 Nm. The temperature rise of brake drum assembly is

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Question: An automobile vehicle weighing 13.5 kN is moving on a level road at a speed of 95 km/h. When the brakes are applied, it is subjected to a uniform deceleration of 6 m/s2. There are brakes on all four wheels. The tyre diameter is 750 mm. The kinetic energy of the rotating parts is 10% of the kinetic energy of the moving vehicle. The mass of each brake drum assembly is 10 kg and the specific heat capacity is 460 J/kg°C. Calculate (i) the braking time; (ii) the braking distance; (iii) the total energy absorbed by each brake; (iv) the torque capacity of each brake; and (v) the temperature rise of brake drum assembly.

Asked by adarsh

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(i) To calculate the braking time, we can use the formula: t = (final velocity - initial velocity) / deceleration First, we need to convert the initial velocity (95 km/h) to meters per second (m/s): Initial velocity = 95 km/h * (1000 m/km) * (1 h/3600 s) = 26.39 m/s Since the vehicle comes to a stop, the final velocity = 0 m/s. Then, we can find braking time: t = (0 - 26.39 m/s) / (-6 m/s²) = 4.4 s (ii) To calculate the braking distance, we can use the formula: Braking distance = initial velocity * time + 0.5 * deceleration * time² Braking distance = 26.39 m/s * 4.4 s + 0.5 * (-6 m/s²) * (4.4 s)² = 57.85 m (iii) To find the total energy absorbed by each brake, we need to find the kinetic energy (KE) of the vehicle first: KE = 0.5 * mass * initial_velocity² Given that an automobile vehicle weighs 13.5 kN, we first convert it to mass (kg): Mass = 13.5 kN * (1000 N/kN) / 9.81 m/s² = 1375.38 kg Now, we find the kinetic energy of the vehicle: KE = 0.5 * 1375.38 kg * (26.39 m/s)² = 476528.05 J As mentioned in the problem, the kinetic energy of the rotating parts is 10% of the kinetic energy of the moving vehicle: Rotating parts KE = 476528.05 J * 10% = 47652.80 J Then, subtract the rotating parts' kinetic energy from the total kinetic energy to get the energy absorbed by the brakes: Energy absorbed by brakes = 476528.05 J - 47652.80 J = 428875.25 J Since there are 4 brakes, the total energy absorbed by each brake is: Energy absorbed by each brake = 428875.25 J / 4 = 107218.81 J (iv) To find the torque capacity of each brake, we can first find the angular deceleration (α) using the formula: α = deceleration / radius Given the tire diameter of 750 mm, the radius is 375 mm or 0.375 m. Now, we can find the angular deceleration: α = 6 m/s² / 0.375 m = 16 rad/s² Now, we can find the torque capacity using the formula: Torque capacity = moment of inertia (I) * α The moment of inertia (I) of each brake drum assembly can be found using the formula: I = 0.5 * m * r², where m is the mass and r is the radius With a mass of 10 kg for each brake drum assembly, the moment of inertia is: I = 0.5 * 10 kg * (0.375 m)² = 0.703 kg·m² Now, we can find the torque capacity: Torque capacity = 0.703 kg·m² * 16 rad/s² = 11.25 N·m (v) To find the temperature rise of the brake drum assembly, we can use the formula: Temperature rise = (Energy absorbed by each brake) / (mass of brake drum assembly * specific heat capacity) Temperature rise = 107218.81 J / (10 kg * 460 J/kg°C) = 23.3°C

Answered by gpt-4

May 8, 2023, 7 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user adarsh's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Monday, May 8, 2023

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