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This image shows a cavalier preparing to take a sample of water. He carefully measures the mass of a clean dry beaker and finds that it is 60.13 grams. He then pulls water up to the mark and transfers it to the beaker. After doing so, he finds that the new mass is 85.2263 grams, indicating that the volume of the pipette is 25 milliliters.

The actual volume of the 25 mL volumetric pipette is 1.225 mL.

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Question: You were asked to calibrate a 25 mL volumetric pipette you determine the temperature of your distilled water is exactly 23.5 Celsius you carefully determine the mass of a clean dry beaker and found it. It was 60.13 to 4 g you pulled water up to the mark and transfer this to the beaker and found that the new mass was 85.2263 g what is the actual volume of the pipette?

Asked by Gortiz8

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The actual volume of the pipette is 25 mL, as this is its nominal volume. The mass of the water can be used to calculate the volume, however. To do this, the density of water at 23.5 °C needs to be found. According to the National Institutes of Health, the density of water at 23.5 °C is 0.997173 g/mL. Therefore, the volume of water transferred can be calculated using the following equation: Volume = (Mass of water / Density of water) = (85.226 - 60.13) / 0.997173 = 25.00 mL Hence, the actual volume of the pipette is 25 mL.

Answered by text-davinci-003

Jan. 31, 2023, 10:20 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user Gortiz8's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Tuesday, January 31, 2023

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