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To simplify the expression \((b^2 - 2b + 4)(b - 2)\), you need to distribute each term in the first polynomial across each term in the second polynomial. Here's a step-by-step method using the distributive property: 1. Distribute \(b^2\) across \((b - 2)\): \[ b^2 \cdot (b - 2) = b^2 \cdot b + b^2 \cdot (-2) = b^3 - 2b^2 \] 2. Distribute \(-2b\) across \((b - 2)\): \[ -2b \cdot (b - 2) = -2b \cdot b + -2b \cdot (-2) = -2b^2 + 4b \] 3. Distribute \(4\) across \((b - 2)\): \[ 4 \cdot (b - 2) = 4 \cdot b + 4 \cdot (-2) = 4b - 8 \] Now, sum all the distributed terms together: \[ b^3 - 2b^2 - 2b^2 + 4b + 4b - 8 \] Combine the like terms: \[ b^3 + (-2b^2 - 2b^2) + (4b + 4b) - 8 = b^3 - 4b^2 + 8b - 8 \] So, the simplified form of the expression \((b^2 - 2b + 4)(b - 2)\) is: \[ b^3 - 4b^2 + 8b - 8 \]
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