"Rashaad wants to rent a car, knowing that: He plans to drive 475 miles. He has at most $250 to spend."

To write an inequality representing \( d \), the total number of days Rashaad can rent the car while staying within his budget, follow these steps: 1. Determine the cost per day: $53. 2. Determine the cost per mile: $0.08. 3. Calculate the cost for driving 475 miles: \[ 0.08 \, \text{dollars/mile} \times 475 \, \text{miles} = 38 \, \text{dollars} \] 4. Set up the inequality to ensure the total cost does not exceed $250: \[ \text{Daily Cost} \times d + \text{Mileage Cost} \leq \text{Budget} \] \[ 53d + 38 \leq 250 \] 5. Solve the inequality for \( d \): \[ 53d + 38 \leq 250 \] \[ 53d \leq 250 - 38 \] \[ 53d \leq 212 \] \[ d \leq \frac{212}{53} \] \[ d \leq 4 \] Therefore, the inequality representing the total number of days Rashaad can rent the car while staying within his budget is: \[ d \leq 4 \]

Since we don't have a drop-down menu to interact with, I'll write the inequality directly. Rashaad will be paying $53 per day for the car and $0.08 for every mile driven. Given he's driving 475 miles, that's an additional cost of 475 * $0.08 = $38. The total cost of his rental, if he rents for "d" days will be (53d + 38). Since Rashaad has $250 to spend, to stay within his budget, the total cost needs to be less than or equal to his budget. We express this as: 53d + 38 <= 250

Let d be the number of days Rashaad is renting the car. The cost of renting the car for d days and driving 475 miles can be given by: Cost = 53d + 0.08(475) × d Cost = 53d + 38d Cost = 91d To stay within the budget of $250, we can write the inequality: 91d ≤ 250 Solving for d: d ≤ 250/91 d ≤ 2.747 d ≤ 2 (approx.) Therefore, Rashaad can rent the car for at most 2 days and stay within his budget. The inequality representing this situation is: 91d ≤ 250 where d is the number of days Rashaad can rent the car.