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To determine the probability of the offspring having wrinkled green seeds, let's break down the genotypes involved:

1. The first plant has the genotype **SsYy** (smooth and yellow).
2. The second plant has the genotype **SSYY** (smooth and yellow).

Now, let's analyze the alleles:

- For seed coat texture:
  - **S** (smooth) is dominant and **s** (wrinkled) is recessive.
- For seed coat color:
  - **Y** (yellow) is dominant and **y** (green) is recessive.

**Crossing the genotypes:**
1. Looking

Probability of Offspring Having Wrinkled, Green Seeds from Cross of SsYy and SSYY Plants: 0%

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Question: Directions: The information below concerns alleles in a pea plant. Use the information to answer any questions that follow. In pea plants, the gene for smooth seed coat (S) is dominant, and the gene for wrinkled seed coat (s) is recA plant with genotype SsYy is crossed with a plant with genotype SSYY. What is the probability that the offspring of these plants will have wrinkled, green seeds? A. 0% B. 100% C. 75% D. 25%essive. The gene for yellow seed coat (Y) is dominant over the recessive gene for green seed coat (y).

Asked by Hafiz

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To determine the probability that the offspring of the plants will have wrinkled, green seeds, we need to analyze the given genotypes of the parents and predict the genotypes of the offspring. Let's break it down step-by-step: 1. **Determine the alleles contributed by each parent:** - Parent 1: SsYy (heterozygous for both traits) - Parent 2: SSYY (homozygous dominant for both traits) 2. **Identify the possible gametes from each parent:** - Parent 1 (SsYy) can produce four different combinations of alleles: SY, Sy, sY, sy. - Parent 2 (SSYY) can only produce one type of gamete: SY. 3. **Determine the genotypes of the offspring by combining the gametes:** - The possible combinations are: - SY (from Parent 1) with SY (from Parent 2) = SSYY (homozygous dominant for both traits) - Sy (from Parent 1) with SY (from Parent 2) = SSYy (heterozygous dominant for the seed coat and homozygous dominant for the seed color) - sY (from Parent 1) with SY (from Parent 2) = SsYY (heterozygous for the seed coat and homozygous dominant for the seed color) - sy (from Parent 1) with SY (from Parent 2) = SsYy (heterozygous for both traits) 4. **Determine the phenotypes of the offspring:** - SSYY: Smooth, yellow seeds - SSYy: Smooth, yellow seeds - SsYY: Smooth, yellow seeds - SsYy: Smooth, yellow seeds All possible offspring have smooth, yellow seeds because they all have at least one dominant allele for each trait (smooth seed coat (S) and yellow seed coat (Y)). 5. **Determine the probability of getting wrinkled, green seeds:** - Wrinkled seeds require the genotype ss (recessive for seed coat). - Green seeds require the genotype yy (recessive for seed color). As none of the gamete combinations produce an offspring with both recessive alleles for seed coat and seed color (ssyy), it is not possible for the offspring to have wrinkled, green seeds. Therefore, the probability of the offspring having wrinkled, green seeds is: **A. 0% (zero percent)**

Answered by gpt-4o

Dec. 17, 2024, 11:45 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user Hafiz's question. Images were generated with OpenAI's AI model, DALL·E 3. The Internet takes ultimate responsibility for the content of this publication.
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Published: Tuesday, December 17, 2024

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