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Question: A 1.00g sample of an acid, HA of unknown molecular mass is dissolved in water and 22.72 cm3 of 0.60 M NaOH solution added to it in a neutralization reaction. HA + NaOH NaA + H2O Exactly 7.84 cm3 of 0.530 M HCl was required to neutralize excess hydroxide by back titration. What is the molecular mass of HA? HCl + NaOH NaCl + H2
To calculate the molecular mass of HA, we will first determine the number of moles of HA that reacted with NaOH. Then, we can use that information to find the molecular mass of HA. 1. Calculate the moles of NaOH that reacted with HCl in the back titration. Moles of NaOH = Molarity of HCl × Volume of HCl Moles of NaOH = 0.530 mol/L × 7.84 cm³ × (1 L/1000 cm³) Moles of NaOH = 0.0041616 mol 2. Calculate the total moles of NaOH that was added in the beginning. Total moles of NaOH = Molarity of NaOH × Volume of NaOH Total moles of NaOH = 0.60 mol/L × 22.72 cm³ × (1 L/1000 cm³) Total moles of NaOH = 0.013632 mol 3. Calculate the moles of NaOH that reacted with HA. Moles of NaOH reacted with HA = Total moles of NaOH - Moles of NaOH reacted with HCl Moles of NaOH reacted with HA = 0.013632 mol - 0.0041616 mol Moles of NaOH reacted with HA = 0.0094704 mol 4. Since the reaction between HA and NaOH has a 1:1 molar ratio, the moles of HA that reacted with NaOH are equal to the moles of NaOH that reacted with HA. Moles of HA = 0.0094704 mol 5. Calculate the molecular mass of HA. Molecular mass of HA = Mass of HA / Moles of HA Molecular mass of HA = 1.00 g / 0.0094704 mol Molecular mass of HA ≈ 105.6 g/mol The molecular mass of HA is approximately 105.6 g/mol.
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