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Question: Sir Isaac Newton drops an apple from the top of a building. The apple falls 2.0 m in 1 second. If it has fallen 149 m by the 50th second, how many meters would the apple have fallen after 12 seconds
The distance an object falls due to gravity over time can be modeled by the equation d = 0.5 * g * t^2, where d is the distance, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is time in seconds. Given that the apple falls 2m in the 1st second, we can ignore the air resistance or other forces and assume the apple's falling speed is continuously accelerated by gravity. So after 12 seconds, using the formula, we get: d = 0.5 * 9.8 * (12^2) = 705.6 meters So, the apple would have fallen approximately 706 meters after 12 seconds.
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