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Question: if 6/k=24/k+30 what is the value of k/6? A.5/3 B.3/5 C.10 D.6
To solve the equation \(\frac{6}{k} = \frac{24}{k} + 30\), let's start by eliminating the fractions. Multiply every term by \(k\) to get rid of the denominators: \[ 6 = 24 + 30k \] Next, isolate the term involving \(k\). Subtract 24 from both sides: \[ 6 - 24 = 30k \] This simplifies to: \[ -18 = 30k \] Now, solve for \(k\) by dividing both sides by 30: \[ k = \frac{-18}{30} \] Simplify the fraction: \[ k = \frac{-3}{5} \] Now, we need to find the value of \(\frac{k}{6}\): \[ \frac{k}{6} = \frac{\frac{-3}{5}}{6} = \frac{-3}{5} \times \frac{1}{6} = \frac{-3}{30} = \frac{-1}{10} \] So it looks like there might be a discrepancy unless there was a typo or mistake along the way, please verify the original question and re-check calculations where necessary. The correct answer based on the provided options does not include \(-\frac{1}{10}\). Let's check our steps carefully again to confirm the correctness. If verified as correct from original data, it is indeed functionally aligned with steps. Would you like to review and verify initial conditions or discuss anything else?
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