Ask AI: if 25.00 mL of citric acid solution is titrated with 28.12 mL of 0.1718N KOH, what is the concentration of citric acid? (2 decimal place answer)

To determine the concentration of citric acid, we need to understand the titration process and the stoichiometry of the reaction between citric acid and KOH. Citric acid is a triprotic acid, which means it can donate three protons (H⁺). The balanced chemical equation for the reaction in this context is: \[ \text{C}_6\text{H}_8\text{O}_7 (aq) + 3 \text{KOH} (aq) \rightarrow \text{K}_3\text{C}_6\text{H}_5\text{O}_7 (aq) + 3 \text{H}_2\text{O} (l) \] Here, one mole of citric acid reacts with three moles of KOH. 1. Calculate the moles of KOH used: Given: \[ \text{Volume of KOH} = 28.12 \, \text{mL} \] \[ \text{Normality (N)} = 0.1718 \, \text{N} \] Normality (N) = Molarity (M) × number of equivalents For KOH, equivalents in this reaction would be 1 (since KOH can donate one OH⁻ per molecule). Moles of KOH \( = \text{Volume (L)} \times \text{Normality} \) \[ = 0.02812 \, \text{L} \times 0.1718 \, \text{N} \] \[ = 0.004832 \, \text{moles of KOH} \] 2. Relate moles of KOH to moles of citric acid: According to the reaction, 3 moles of KOH react with 1 mole of citric acid: \[ \text{Moles of citric acid} = \frac{\text{Moles of KOH}}{3} \] \[ = \frac{0.004832}{3} \] \[ = 0.001611 \, \text{moles of citric acid} \] 3. Calculate the molarity (concentration) of citric acid: \[ \text{Molarity (M)} = \frac{\text{Moles of solute}}{\text{Volume of solution (L)}} \] Given volume of citric acid solution: \[ \text{Volume} = 25.00 \, \text{mL} = 0.02500 \, \text{L} \] \[ \text{Molarity} = \frac{0.001611 \, \text{moles}}{0.02500 \, \text{L}} \] \[ = 0.06444 \, \text{M} \] Rounding to two decimal places: \[ \boxed{0.06 \, \text{M}} \] Therefore, the concentration of the citric acid solution is 0.06 M.

To find the concentration of citric acid in the solution, we can use the formula: (Concentration of the base) × (Volume of the base) = (Concentration of the acid) × (Volume of the acid) We are given: - Volume of KOH: 28.12 mL - Normality of KOH: 0.1718 N - Volume of citric acid: 25.00 mL Let x be the concentration of citric acid (in normality). We can solve for x by setting up the equation: (0.1718 N) × (28.12 mL) = x × (25.00 mL) Now, solve for x: x = (0.1718 N × 28.12 mL) / 25.00 mL x = 0.19348 N To get the answer rounded to two decimal places, the concentration of citric acid is: x ≈ 0.19 N