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Question: A bowling ball of mass 8.3 kg moves in a straight line at 1.96 m/s. How fast must a Ping-Pong ball of mass 1.084 g move in a straight line so that the two balls have the same momentum?
Momentum (p) is calculated by the formula p = mv, where m is the mass and v is the velocity. In order to calculate the velocity of the Ping-Pong ball to have the same momentum as the bowling ball, we first need to find the momentum of the bowling ball. The momentum of the bowling ball is: p = mv = (8.3 kg) * (1.96 m/s) = 16.268 kg*m/s. Now, let's find the required velocity for the Ping-Pong ball which should be in meters/second for correct units. However, first we need to convert the Ping-Pong ball's mass from grams to kilograms: 1.084 g = 0.001084 kg. Now, we can use the momentum formula to find the velocity (v) of the Ping-Pong ball to achieve the same momentum as the bowling ball: 16.268 kg*m/s = (0.001084 kg) * v v = 16.268 / 0.001084 = 15,002.21 m/s. Therefore, in order for a Ping-Pong ball to have the same momentum as the given bowling ball, it must travel at a speed of approximately 15,002.21 meters per second.
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