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Question: Find the general term of the following 4, 12, 36,
Here, each term is multiplied by 3 to get the next term. So, this is clearly a geometric progression. The general form of a geometric progression is: a(n) = a * r^(n-1) where "a" is the first term of the sequence, "r" is the common ratio (which is the multiple from one term to the next), and "n" is the position of the term in the sequence. Here, a = 4 (the first term) and r = 3 (since each term is multiplied by 3 to get the next term). So, the general term of this sequence would be: a(n) = 4 * 3^(n-1).
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