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Question: A farmer finds the mean mass for a random sample of 200 eggs laid by his hens to be 57.2 grams. If the masses of eggs for this breed of hen are normally distributed with standard deviation 1.5 grams, estimate the mean mass, to the nearest tenth of a gram, of the eggs for this breed using a 90% confidence interval.
To estimate the mean mass of the eggs for this breed using a 90% confidence interval, we need to use the following formula: CI = X̄ ± Z * (σ / √n) where CI is the confidence interval, X̄ is the sample mean, Z is the Z-score associated with the desired confidence level, σ is the population standard deviation, and n is the sample size. We are given the following information: - X̄ = 57.2 grams (sample mean) - σ = 1.5 grams (standard deviation) - n = 200 (sample size) To find the Z-score associated with a 90% confidence interval, we should look at a Z-table. The Z-score for a 90% confidence interval is 1.645 (in a two-tailed test, alpha will be divided by 2, so actually we are looking for Z(0.95) on the table). Now, we can plug in the values into the formula: CI = 57.2 ± 1.645 * (1.5 / √200) CI = 57.2 ± 1.645 * (1.5 / 14.1421) CI = 57.2 ± 1.645 * 0.1061 CI = 57.2 ± 0.1746 So the 90% confidence interval is (57.0254, 57.3746). To the nearest tenth of a gram, we can estimate the mean mass of eggs for this breed to be between 57.0 grams and 57.4 grams.
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