Ask AI on The Internet
Question: Differentiate with respect to x. a. y=x^2sin^-1(x/2) b. y=tan^-1(tanx)
To differentiate the given functions with respect to x, we will apply the chain rule and other differentiation rules as needed. The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function. a. y = x^2*sin^(-1)(x/2) Let's differentiate step by step: 1. Differentiate x^2 with respect to x: d(x^2)/dx = 2x. 2. Differentiate sin^(-1)(x/2) with respect to (x/2): d(sin^(-1)(x/2))/d(x/2) = 1/√(1-(x/2)^2). 3. Differentiate (x/2) with respect to x: d(x/2)/dx = 1/2. Now we'll use the chain rule: dy/dx = (2x) * (1/√(1-(x/2)^2)) * (1/2). Combining, we get: dy/dx = x/√(1-(x^2)/4). b. y = tan^(-1)(tan(x)) Since tan^(-1)(tan(x)) simplifies to x, within their respective domains: dy/dx = d(x)/dx = 1.
A new large language model has been made available since this question was asked.
To generate an updated answer from the new model, click the button below.
Think your answer is better than the AI's? Post it below.
Other Most Relevant Posts:
Question Tags
If you want your question answered by an AI, click here.
Post your own comment: