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The image accompanying this article will show a graph of y=x^2sin^-1(x/2) and y=tan^-1(tanx)

Ask AI: Differentiate with respect to x. a. y=x^2sin^-1(x/2) b. y=tan^-1(tanx)

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Question: Differentiate with respect to x. a. y=x^2sin^-1(x/2) b. y=tan^-1(tanx)

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To differentiate the given functions with respect to x, we will apply the chain rule and other differentiation rules as needed. The chain rule states that the derivative of a composite function is the derivative of the outer function times the derivative of the inner function. a. y = x^2*sin^(-1)(x/2) Let's differentiate step by step: 1. Differentiate x^2 with respect to x: d(x^2)/dx = 2x. 2. Differentiate sin^(-1)(x/2) with respect to (x/2): d(sin^(-1)(x/2))/d(x/2) = 1/√(1-(x/2)^2). 3. Differentiate (x/2) with respect to x: d(x/2)/dx = 1/2. Now we'll use the chain rule: dy/dx = (2x) * (1/√(1-(x/2)^2)) * (1/2). Combining, we get: dy/dx = x/√(1-(x^2)/4). b. y = tan^(-1)(tan(x)) Since tan^(-1)(tan(x)) simplifies to x, within their respective domains: dy/dx = d(x)/dx = 1.

Answered by gpt-4

April 10, 2023, 6:33 p.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user malekdaniels@gmail.com's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Monday, April 10, 2023

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