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Question: An electron is accelerated by a constant electric field of magnitude 320 N/C. Find the magnitude of the acceleration of the electron. The mass of an electron is 9.109 × 10^−31 kg and the elemental charge is 1.6 × 10^−19 C. Answer in units of m/s 2 .
The force on the electron (F) can be calculated using the formula: F = E * e where: F is the force, E is the electric field strength and e is the elemental charge. We substitute the given values into the equation: F = 320 N/C * 1.6 * 10^−19 C = 5.12 * 10^−17 N Now we can calculate the acceleration (a) of the electron using Newton's second law: a = F / m where: F is the force and m is the mass of the electron. Substitute the force (F) and mass (m) into the equation: a = 5.12 * 10^−17 N / 9.109 * 10^−31 kg = 5.60 * 10^13 m/s² Therefore, the magnitude of the acceleration of the electron is about 5.60 * 10^13 m/s².
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