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Question: 19.0 Ω, 9.00 Ω, and 3.00 Ω resistors are connected in series with an emf source. The current in the 9.00 Ω resistor is measured to be 2.50 A. a) Calculate the equivalent resistance of the three resistors in the circuit. b) Find the potential difference across the emf source. c) Find the current in the other resistors.
a) To calculate the equivalent resistance of the three resistors in series, you simply add their resistances together. Req = R1 + R2 + R3 Req = 19.0 Ω + 9.00 Ω + 3.00 Ω Req = 31.0 Ω b) The potential difference across the emf source (or the voltage) can be found by using Ohm's law: V = I*R. We were given the current in the 9.00 Ω resistor as I = 2.50 A. This current flows through the whole circuit in series connection. So, the total voltage is: V = I * Req V = 2.50 A * 31.0 Ω V = 77.5 V c) In a series circuit, the current is the same at all points. Hence, the current in the 19.0 Ω and 3.00 Ω resistors is also 2.50 A.
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