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Question: A .08Kg ball is dropped from a height of 3m. The ball bounces back up to a height of 1.2m. How much mechanical energy was transferred from the ball to the environment?
The mechanical energy that was transferred from the ball to the environment can be found by first calculating the gravitational potential energy before and after the ball's bounce, and then finding the difference. Gravitational potential energy is given by the equation PE = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (approximately 9.8m/s^2 on Earth), and h is height in meters. Before the bounce, the ball's gravitational potential energy was: PE_initial = m*g*h_initial = 0.08kg * 9.8m/s^2 * 3m = 2.352 joules After the bounce, the ball's gravitational potential energy is: PE_final = m*g*h_final = 0.08kg * 9.8m/s^2 * 1.2m = 0.94176 joules The ball lost mechanical energy as it transferred it to the environment in the form of heat, sound, friction, and other forms of energy. This is the difference between the two energies you found: ΔPE = PE_initial - PE_final = 2.352 joules - 0.94176 joules = 1.41024 joules Therefore, the ball transferred approximately 1.41024 joules of mechanical energy to the environment.
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