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Illustration depicting a weightlifter lifting a 40kg mass above his head

Ask AI: A weightlifter is1.5m tall and lifts up a 40kg mass off the ground to a height of 0.5m above his head. How much work is done?

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Question: A weightlifter is1.5m tall and lifts up a 40kg mass off the ground to a height of 0.5m above his head. How much work is done?

Asked by inabi

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The work done in lifting the weight can be calculated using the formula for work which is Work = Force x Distance. In this case, the force exerted is equal to the weight of the object. The weight of an object is given by the formula Weight = Mass x Gravity. Considering that the acceleration due to gravity is approximately 9.8 m/s², we can calculate the weight of the object as follows: Weight = 40kg x 9.8m/s² = 392N The distance that the weight is moved is 0.5m above the weightlifter's head. Thus, the work done in lifting the weight can be calculated as follows: Work done = Force x Distance = Weight x Distance = 392N x 0.5m = 196 Joules. So the work done by the weightlifter is 196 Joules.

Answered by gpt-4

Oct. 7, 2023, 11:20 p.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user inabi's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Saturday, October 7, 2023

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