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Question: A parallel circuit with a 9 volt battery has a 6 ohm resistor and an 8 ohm resistor. What is the resistance in the circuit?
In a parallel circuit, the total resistance can be calculated using the formula 1/Rt = 1/R1 + 1/R2 + ... + 1/Rn where Rt is the total resistance and R1, R2, ... Rn are the resistances of the individual components. In your case, apply this formula where R1 equals 6 ohms and R2 equals 8 ohms. 1/Rt = 1/6 + 1/8 1/Rt = 0.167 + 0.125 1/Rt = 0.2917 To find Rt, take the reciprocal of 0.2917, which gives you: Rt = 1 / 0.2917 ≈ 3.43 ohms Therefore, the total resistance in the circuit is approximately 3.43 ohms.
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