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Question: A 2-kg ball with an initial speed of 4 m/s sticks to a wall after colliding with the wall. How much kinetic energy is lost during the collision?
The kinetic energy before the collision can be calculated using the formula KE1 = 0.5*m*v^2, where m represents the mass of the ball and v its initial speed. For the given, the mass m is 2 kg and the initial speed v is 4 m/s, so: KE1 = 0.5*2*4^2 = 16 Joules. After the ball sticks to the wall, it stops moving, so its final speed is 0 and thus its kinetic energy (KE2) is 0 as well. The kinetic energy lost during the collision would be the difference in the kinetic energy before and after the collision, which simply is the initial kinetic energy itself in this process. So, the kinetic energy lost is 16 - 0 = 16 Joules.
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