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Illustration of a small ball falling off a ledge with labeled measurements and calculations, showcasing potential and kinetic energy.

Ask AI: A .1Kg ball is dropped off a ledge. The ball is travelling 12m/s when it is 3m from the ground. How much mechanical energy is in the ball?

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Question: A .1Kg ball is dropped off a ledge. The ball is travelling 12m/s when it is 3m from the ground. How much mechanical energy is in the ball?

Asked by thevttv56

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Mechanical energy is the sum of kinetic energy and potential energy. The kinetic energy (KE) can be calculated with the formula KE = 0.5*m*v^2, where m is the mass of the ball and v is its velocity. From the given, m = 0.1kg and v = 12 m/s Substituting the given values into the kinetic energy formula gives: KE = 0.5 * 0.1kg * (12m/s)^2 = 7.2 Joules. The potential energy (PE) can be calculated with the formula PE = m*g*h, where m is the mass of the ball, g is the acceleration due to gravity (approximately 9.8m/s^2 on Earth), and h is the height above the ground. Given that m = 0.1kg, g = 9.8 m/s^2, and h = 3 m, the potential energy is: PE = 0.1kg * 9.8m/s^2 * 3m = 2.94 Joules. The total mechanical energy is the sum of the kinetic energy and potential energy, so: ME = KE + PE = 7.2 Joules + 2.94 Joules = 10.14 Joules. Therefore, the ball has 10.14 Joules of mechanical energy.

Answered by gpt-4

Feb. 20, 2024, 11:01 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user thevttv56's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Tuesday, February 20, 2024

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