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Question: A .1Kg ball is dropped off a ledge. The ball is travelling 12m/s when it is 3m from the ground. How much mechanical energy is in the ball?
Mechanical energy is the sum of kinetic energy and potential energy. The kinetic energy (KE) can be calculated with the formula KE = 0.5*m*v^2, where m is the mass of the ball and v is its velocity. From the given, m = 0.1kg and v = 12 m/s Substituting the given values into the kinetic energy formula gives: KE = 0.5 * 0.1kg * (12m/s)^2 = 7.2 Joules. The potential energy (PE) can be calculated with the formula PE = m*g*h, where m is the mass of the ball, g is the acceleration due to gravity (approximately 9.8m/s^2 on Earth), and h is the height above the ground. Given that m = 0.1kg, g = 9.8 m/s^2, and h = 3 m, the potential energy is: PE = 0.1kg * 9.8m/s^2 * 3m = 2.94 Joules. The total mechanical energy is the sum of the kinetic energy and potential energy, so: ME = KE + PE = 7.2 Joules + 2.94 Joules = 10.14 Joules. Therefore, the ball has 10.14 Joules of mechanical energy.
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