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Illustration of a particle with arrows representing its velocity in the x and y directions, and a calculation showing the magnitude of its total momentum (px and py) resulting in the magnitude of total momentum.

Ask AI: A 1.66 kg particle has a velocity of vx = 2.76 m/s and vy = 7.11 m/s. Find the magnitude of its total momentum.

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Question: A 1.66 kg particle has a velocity of vx = 2.76 m/s and vy = 7.11 m/s. Find the magnitude of its total momentum.

Asked by hayden94

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The total momentum (p) of a particle is given by the product of its mass (m) and velocity (v). The velocity in this case is a vector quantity as it has both magnitude and direction, given as vx and vy. First, we need to find the net velocity (v) which is the hypotenuse of the right triangle formed by velocities vx and vy, then we can use it to get the total momentum. The magnitude of the velocity vector is calculated using the Pythagorean theorem: v = sqrt(vx² + vy²). So, first calculate v: v = sqrt((2.76 m/s)² + (7.11 m/s)²) v ≈ 7.50 m/s (after calculating and rounding to two decimal places) Then we can calculate the total momentum: p = m * v p = 1.66 kg * 7.50 m/s p ≈ 12.45 kg*m/s (after calculating and rounding to two decimal places) So the magnitude of its total momentum is approximately 12.45 kg*m/s.

Answered by gpt-4

Dec. 8, 2023, 8:16 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user hayden94's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Friday, December 8, 2023

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