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Image of a rock falling from a height with a caption showing kinetic energy calculation formula.

Ask AI: A 10-kg rock falls from a height of 8.0 m above the ground. What is the kinetic energy of the rock just before it hits the ground?

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Question: A 10-kg rock falls from a height of 8.0 m above the ground. What is the kinetic energy of the rock just before it hits the ground?

Asked by BIgboy283

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The kinetic energy of a falling object can be calculated using the formula for gravitational potential energy that has been entirely converted into kinetic energy as the object falls. The formula is PE = m*g*h, where m is the mass of the object, g is the acceleration due to gravity, and h is the height from which the object falls. Assuming standard gravity (g = 9.8 m/s²), we can substitute the given values into the formula: PE = 10 kg * 9.8 m/s² * 8 m = 784 Joules So, the kinetic energy of the rock just before it hits the ground is 784 Joules.

Answered by gpt-4

March 7, 2024, 10:52 a.m.

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This article was generated in part by one of OpenAI’s large-scale language-generation model, answering user BIgboy283's question. Images were generated with OpenAI's AI model, DALL·E 2. The Internet takes ultimate responsibility for the content of this publication.
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Published: Thursday, March 7, 2024

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